Comments on: Getting Multiple Array Form Values With PHP

By: neo99

neo99 — Wed, 19 Oct 2011 06:21:06 +0000

Thank you very much. You know what, your posting really saved me from headache and heartache. I really appreciate what you have posted on your website.

You are awesome man, uber cool! “-)

By: kema

kema — Thu, 07 Jul 2011 10:15:42 +0000

I like your coding and will like to share some projects with you for your assistant.

By: simon

simon — Tue, 14 Dec 2010 13:52:36 +0000

soory again, my last comment woked it out, I had to put the “$inserted_user_id = $db->last_insert_id();” outside the loop!

cheers

By: simon

simon — Tue, 14 Dec 2010 13:16:37 +0000

sorry it seems to leave the code out but I have a the if and for you illustrate above to get the $fields and $fields2 variables

it must have some to do with the last insert id line? I can’T work it out

$inserted_user_id = $db->last_insert_id();

By: simon

simon — Tue, 14 Dec 2010 13:10:53 +0000

in the above code
for ( $i=0;$ilast_insert_id();

should read

for ( $i=0;$ilast_insert_id();

By: simon

simon — Tue, 14 Dec 2010 13:07:50 +0000

HI great tutorial, including the adding unlimited form fileds one.

I have one problem when comes to adding the values to the database. I seem to have got it so USER 1 is entered OK, I also have it so that if I add 3 websites they are all entered as such going thru the for loop.

websiteID website_url website_title
1 1 t1
2 2 t2
3 3 t3

the problem comes when the website ID ar give a user ID, the websites 2 & 3 are given a 0 user ID

here is my code, any help to get the user ID added to the 2 and 3 records woud great
===========
if (isset($_POST['fields'])) {

for ( $i=0;$ilast_insert_id();

$sql_website = sprintf(“INSERT INTO websites (Website_URL, Website_Title) VALUES (‘%s’,'%s’)”,
mysql_real_escape_string($fields),
mysql_real_escape_string($fields2));
$result_website = $db->query($sql_website);
$inserted_website_id = $db->last_insert_id();

//Insert into users_websites_link table
$sql_users_website = sprintf(“INSERT INTO users_websites_link (UserID, WebsiteID) VALUES (‘%s’,'%s’)”,
mysql_real_escape_string($inserted_user_id),
mysql_real_escape_string($inserted_website_id) );
$result_users_website = $db->query($sql_users_website);

==========

By: Rob

Rob — Sun, 12 Dec 2010 18:44:04 +0000

@charles

You’d simply use thew ‘files’ array, instead of the ‘post’ array. E.g. assuming you’re using a file input called ‘the_file’ and have added enctype=”multipart/form-data” to your form tag, you’d access the file name of a particular file like:

$file_name = $_FILES["the_file"]["name"][$i];

hope that helps!

By: charles

charles — Mon, 06 Dec 2010 10:00:44 +0000

how do you go about it if the one of the elements is file?

By: James

James — Thu, 22 Apr 2010 19:06:13 +0000

Thanks for this Rob, working like a gem, however I also have multiple Radio buttons being created and since their name is the same across each addition, you can’t select just one. If that makes sense. Also having trouble with form validation since fields share the same name.

Any tips would be great!

Thank you.

By: Rob

Rob — Tue, 29 Sep 2009 19:18:27 +0000

@dudu

I’m not exactly sure what you mean? My example is based purely on a HTML form, using PHP to read the results. Using MySQL or SQL doesn’t come into it currently

You could of course use the values within the loop to insert into a MS SQL database (as oppossed to MySQL). E.g. you’d have your insert statement within for loop. More on the latter is in a previous article I wrote, see http://www.web-design-talk.co.uk/58/adding-unlimited-form-fields-with-jquery-mysql/